When trying to debug in vscode, the vscode generate launch.json
config file. When I try to debug, it first tries to compile the source and then debug the exe. I would like to just debug already compiled executable (compiled with gcc -g
option).
The json file is:
{
// Use IntelliSense to learn about possible attributes.
// Hover to view descriptions of existing attributes.
// For more information, visit: https://go.microsoft.com/fwlink/?linkid=830387
"version": "0.2.0",
"configurations": [
{
"name": "gcc-10 - Build and debug active file",
"type": "cppdbg",
"request": "launch",
"program": "${fileDirname}/${fileBasenameNoExtension}",
"args": [
"-pthread",
"common.c"
],
"stopAtEntry": false,
"cwd": "${workspaceFolder}",
"environment": [],
"externalConsole": false,
"MIMode": "gdb",
"setupCommands": [
{
"description": "Enable pretty-printing for gdb",
"text": "-enable-pretty-printing",
"ignoreFailures": true
}
],
"preLaunchTask": "C/C++: gcc-10 build active file",
"miDebuggerPath": "/usr/bin/gdb"
}
]
}
Can I make somehow the vsode to not compile but just debug with already compiled source to "program":"${fileDirname}/${fileBasenameNoExtension}"
, I have compiled to the very same name - no extension in current directory, as the property suggest. So how to make vscode to take this executable as its debug file?
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