Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
413 views
in Technique[技术] by (71.8m points)

iphone - UIStoryboardPopoverSegue opening multiple windows on button touch

I'm using a UIStoryboardPopoverSegue to present a popover for an iOS 5 iPad app. The Segue works great, but it seems like the toolbar that contains the button is a passthrough view for the popover controller so if you keep pressing the button, more popovers appear. As I'm not creating and keeping track of the UIPopoverController myself (as the Storyboard is doing it) I can't dismiss it when the button is touched again. Has anyone else run into this? I have a bug open with Apple but they haven't responded.

EDIT: I've solved this using the answer below. Here is the code I ended up using. currentPopover is a __weak ivar in my view controller class, so when the controller is done it will drop to nil automatically.

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
    if([segue isKindOfClass:[UIStoryboardPopoverSegue class]]){
        // Dismiss current popover, set new popover
        [currentPopover dismissPopoverAnimated:YES];
        currentPopover = [(UIStoryboardPopoverSegue *)segue popoverController];
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

There are some visual issues with the your solution Cory.

Two options that can be considered - simply remove or change the action of the button that presents the popover.

Option 1, hold a pointer to the button's action, and after the popover is presented, set the action to nil. Upon dismissal of the popover reset to the original action.

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{

    action = [sender action];
    [sender setAction:nil];

    self.currentPopover = [(UIStoryboardPopoverSegue *)segue popoverController];
    self.currentPopover.delegate = self;
}

-(BOOL)popoverControllerShouldDismissPopover:(UIPopoverController *)popoverController
{
    [self.navigationItem.rightBarButtonItem setAction:action];

    return YES;
}

This way the popover can only appear once, and will be dismissed as expected.

A second option would be to change the function of the button so that when the popover is visible, tapping the button will cause the popover to be dismissed.

    -(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
    {

        action = [sender action];
        target = [sender target];

        [sender setTarget:self];
        [sender setAction:@selector(dismiss:)];

        self.currentPopover = [(UIStoryboardPopoverSegue *)segue popoverController];
        self.currentPopover.delegate = self;
    }

-(void)dismiss:(id)sender
{
    [self.navigationItem.rightBarButtonItem setAction:action];
    [self.navigationItem.rightBarButtonItem setTarget:target];
    ////or
//  [sender setAction:action];
//  [sender setTarget:target];
    [self.currentPopover dismissPopoverAnimated:YES];
}


    -(BOOL)popoverControllerShouldDismissPopover:(UIPopoverController *)popoverController
    {
        [self.navigationItem.rightBarButtonItem setAction:action];
        [self.navigationItem.rightBarButtonItem setTarget:target];

        return YES;
    }

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...