Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.3k views
in Technique[技术] by (71.8m points)

regex - replacing square brackets of a string with oracle REGEXP_REPLACE function

I want to replace square brackets in string with REGEXP_REPLACE function. Even I escape these chracters it's not replacing

select regexp_replace('VMI[[DATA]]INFO', '[[]]', '_') from dual;

result

VMI[[DATA]]INFO

How can we do this? Am I missing something?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can do it like this:

select regexp_replace('VMI[[DATA]]INFO', '[|]', '_') from dual;

But I don't think that regular expressions are needed here, you can also use TRANSLATE

select translate('VMI[[DATA]]INFO', '[]', '__') from dual;

Here is a sqlfiddle demo


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...