In general, you can't - Rust does not support variadic functions, except when interoperating with C code that uses varargs.
In this case, since all of your arguments are the same type, you can accept a slice:
fn foo(args: &[&str]) {
for arg in args {
println!("{}", arg);
}
}
fn main() {
foo(&["hello", "world", "I", "am", "arguments"]);
}
(Playground)
Beyond that, you can explicitly accept optional arguments:
fn foo(name: &str, age: Option<u8>) {
match age {
Some(age) => println!("{} is {}.", name, age),
None => println!("Who knows how old {} is?", name),
}
}
fn main() {
foo("Sally", Some(27));
foo("Bill", None);
}
(Playground)
If you need to accept many arguments, optional or not, you can implement a builder:
struct Arguments<'a> {
name: &'a str,
age: Option<u8>,
}
impl<'a> Arguments<'a> {
fn new(name: &'a str) -> Arguments<'a> {
Arguments {
name: name,
age: None
}
}
fn age(self, age: u8) -> Self {
Arguments {
age: Some(age),
..self
}
}
}
fn foo(arg: Arguments) {
match arg.age {
Some(age) => println!("{} is {}.", arg.name, age),
None => println!("Who knows how old {} is?", arg.name),
}
}
fn main() {
foo(Arguments::new("Sally").age(27));
foo(Arguments::new("Bill"));
}
(Playground)
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