Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
814 views
in Technique[技术] by (71.8m points)

rust - How can the ref keyword be avoided when pattern matching in a function taking &self or &mut self?

The Rust book calls the ref keyword "legacy". As I want to follow the implicit advice to avoid ref, how can I do it in the following toy example? You can find the code also on the playground.

struct OwnBox(i32);

impl OwnBox {
    fn ref_mut(&mut self) -> &mut i32 {
        match *self {
            OwnBox(ref mut i) => i,
        }

        // This doesn't work. -- Even not, if the signature of the signature of the function is
        // adapted to take an explcit lifetime 'a and use it here like `&'a mut i`.
        // match *self {
        //     OwnBox(mut i) => &mut i,
        // }

        // This doesn't work
        // match self {
        //     &mut OwnBox(mut i) => &mut i,
        // }
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Since self is of type &mut Self, it is enough to match against itself, while omitting ref entirely. Either dereferencing it with *self or adding & to the match arm would cause an unwanted move.

fn ref_mut(&mut self) -> &mut i32 {
    match self {
        OwnBox(i) => i,
    }
}

For newtypes such as this one however, &mut self.0 would have been enough.

This is thanks to RFC 2005 —?Match Ergonomics.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...