I want to get other process' argv like ps.
I'm using Mac OS X 10.4.11 running on Intel or PowerPC.
First, I read code of ps and man kvm, then I wrote some C code.
#include <kvm.h>
#include <fcntl.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/sysctl.h>
#include <paths.h>
int
main(void) {
char errbuf[1024];
kvm_t *kd = kvm_openfiles(_PATH_DEVNULL, NULL, _PATH_DEVNULL, O_RDONLY, errbuf);
int num_procs;
if (!kd) { fprintf(stderr, "kvm_openfiles failed : %s
", errbuf); return 0; }
struct kinfo_proc *proc_table = kvm_getprocs(kd, KERN_PROC_ALL, 0, &num_procs);
for (int i = 0; i < num_procs; i++) {
struct kinfo_proc *pproc = &proc_table[i];
char **proc_argv = kvm_getargv(kd, pproc, 0);
printf("%p
", proc_argv);
}
kvm_close(kd);
return 0;
}
When ran on PowerPC, kvm_getargv()
always returned NULL. When ran
on Intel, kvm_openfiles()
failed with error /dev/mem: No such file
or directory
.
Of cource, I know about permission.
Second, I tried sysctl.
#include <sys/sysctl.h>
#include <stdio.h>
#include <stdlib.h>
#define pid_of(pproc) pproc->kp_proc.p_pid
int
main(void) {
int mib[4] = { CTL_KERN, KERN_PROC, KERN_PROC_ALL, 0 };
int buffer_size;
sysctl(mib, 4, NULL, &buffer_size, NULL, 0);
struct kinfo_proc *result = malloc(buffer_size);
sysctl(mib, 4, result, &buffer_size, NULL, 0);
int num_procs = buffer_size / sizeof(struct kinfo_proc);
for (int i = 0; i < num_procs; i++) {
struct kinfo_proc *pproc = result + i;
int mib[3] = { CTL_KERN, KERN_PROCARGS, pid_of(pproc) }; // KERN_PROC_ARGS is not defined
char *proc_argv;
int argv_len;
sysctl(mib, 3, NULL, &argv_len, NULL, 0);
proc_argv = malloc(sizeof(char) * argv_len);
sysctl(mib, 3, proc_argv, &argv_len, NULL, 0);
fwrite(proc_argv, sizeof(char), argv_len, stdout);
printf("
");
free(proc_argv);
}
return 0;
}
By fwrite, I got argv[0] but argv[1..] are not (environment variables
are printed out.)
There is no more way to do it?
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