The easiest technique is to just shift the map down, say 40% from where the coordinate
would be, taking advantage of the span
of the region
of the MKMapView
. If you don't need actual pixels, but just need it to move down so that the CLLocationCoordinate2D
in question is near the top of the map (say 10% away from the top):
CLLocationCoordinate2D center = coordinate;
center.latitude -= self.mapView.region.span.latitudeDelta * 0.40;
[self.mapView setCenterCoordinate:center animated:YES];
If you want to account for rotation and pitch of the camera, the above technique may not be adequate. In that case, you could:
Identify the position in the view to which you want to shift the user location;
Convert that to a CLLocation
;
Calculate the distance of the current user location from that new desired location;
Move the camera by that distance in the direction 180° from the current heading of the map's camera.
E.g. in Swift 3, something like:
var point = mapView.convert(mapView.centerCoordinate, toPointTo: view)
point.y -= offset
let coordinate = mapView.convert(point, toCoordinateFrom: view)
let offsetLocation = coordinate.location
let distance = mapView.centerCoordinate.location.distance(from: offsetLocation) / 1000.0
let camera = mapView.camera
let adjustedCenter = mapView.centerCoordinate.adjust(by: distance, at: camera.heading - 180.0)
camera.centerCoordinate = adjustedCenter
Where CLLocationCoordinate2D
has the following extension
:
extension CLLocationCoordinate2D {
var location: CLLocation {
return CLLocation(latitude: latitude, longitude: longitude)
}
private func radians(from degrees: CLLocationDegrees) -> Double {
return degrees * .pi / 180.0
}
private func degrees(from radians: Double) -> CLLocationDegrees {
return radians * 180.0 / .pi
}
func adjust(by distance: CLLocationDistance, at bearing: CLLocationDegrees) -> CLLocationCoordinate2D {
let distanceRadians = distance / 6_371.0 // 6,371 = Earth's radius in km
let bearingRadians = radians(from: bearing)
let fromLatRadians = radians(from: latitude)
let fromLonRadians = radians(from: longitude)
let toLatRadians = asin( sin(fromLatRadians) * cos(distanceRadians)
+ cos(fromLatRadians) * sin(distanceRadians) * cos(bearingRadians) )
var toLonRadians = fromLonRadians + atan2(sin(bearingRadians)
* sin(distanceRadians) * cos(fromLatRadians), cos(distanceRadians)
- sin(fromLatRadians) * sin(toLatRadians))
// adjust toLonRadians to be in the range -180 to +180...
toLonRadians = fmod((toLonRadians + 3.0 * .pi), (2.0 * .pi)) - .pi
let result = CLLocationCoordinate2D(latitude: degrees(from: toLatRadians), longitude: degrees(from: toLonRadians))
return result
}
}
So, even with the camera pitched and at a heading other than due north, this moves the user's location (which is centered, where the lower crosshair is) up 150 pixels (where the upper crosshair is), yielding something like:
Obviously, you should be conscious about degenerate situations (e.g. you're 1 km from the south pole and you try to shift the map up 2 km meters; you're using a camera angle pitched so far that the desired screen location is past the horizon; etc.), but for practical, real-world scenarios, something like the above might be sufficient. Obviously, if you don't let the user change the pitch of the camera, the answer is even easier.
Original answer: for moving the annotation n
pixels
If you have a CLLocationCoordinate2D
, you can convert it to a CGPoint
, move it x pixels, and then convert it back to a CLLocationCoordinate2D
:
- (void)moveCenterByOffset:(CGPoint)offset from:(CLLocationCoordinate2D)coordinate
{
CGPoint point = [self.mapView convertCoordinate:coordinate toPointToView:self.mapView];
point.x += offset.x;
point.y += offset.y;
CLLocationCoordinate2D center = [self.mapView convertPoint:point toCoordinateFromView:self.mapView];
[self.mapView setCenterCoordinate:center animated:YES];
}
You can call this by:
[self moveCenterByOffset:CGPointMake(0, 100) from:coordinate];
Unfortunately, this only works if the coordinate
is visible before you start, so you might have to go to the original coordinate first, and then adjust the center.