Hi I'm quite new to flask and I want to upload a file using an ajax call to the server. As mentioned in the documentation, I added a file upload to the html as folows:
<form action="" method=post enctype="multipart/form-data" id="testid">
<table>
<tr>
<td>
<label>Upload</label>
</td>
<td>
<input id="upload_content_id" type="file" name="upload_file" multiple>
<input type="button" name="btn_uplpad" id="btn_upload_id" class="btn-upload" value="Upload"/>
</td>
</tr>
</table>
</form>
and I wrote the ajax handler as this
$(document).ready(function() {
$("#btn_upload_id" ).click(function() {
$.ajax({
type : "POST",
url : "/uploadajax",
cache: false,
async: false,
success : function (data) {},
error: function (XMLHttpRequest, textStatus, errorThrown) {}
});
});
});
I do not know how to get the uploaded file (not the name) from this
<input id="upload_content_id" type="file" name="upload_file" multiple>
and save the file in folder. I'm not quite sure how to read the file from handler which i have written:
@app.route('/uploadajax', methods = ['POST'])
def upldfile():
if request.method == 'POST':
file_val = request.files['file']
I will be grateful if anyone can help. Thank you in advance
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