x86 - Why can't you set the instruction pointer directly?

Question

The Wikipedia article about x86 assembly says that "the IP register cannot be accessed by the programmer directly."

Directly means with instructions like mov and add.

Why not? What is the reason behind this? What are the technical restrictions?

Answer 1

You can't access it directly because there's no legitimate use case. Having any arbitrary instruction change eip would make branch prediction very difficult, and would probably open up a whole host of security issues.

You can edit eip using jmp, call or ret. You just can't directly read from or write to eip using normal operations

Setting eip to a register is as simple as jmp eax. You can also do push eax; ret, which pushes the value of eax to the stack and then returns (i.e. pops and jumps). The third option is call eax which does a call to the address in eax.

Reading can be done like this:

call get_eip
  get_eip:
pop eax ; eax now contains the address of this instruction