Use datetime.timedelta
:
from datetime import date, datetime, timedelta
def perdelta(start, end, delta):
curr = start
while curr < end:
yield curr
curr += delta
>>> for result in perdelta(date(2011, 10, 10), date(2011, 12, 12), timedelta(days=4)):
... print result
...
2011-10-10
2011-10-14
2011-10-18
2011-10-22
2011-10-26
2011-10-30
2011-11-03
2011-11-07
2011-11-11
2011-11-15
2011-11-19
2011-11-23
2011-11-27
2011-12-01
2011-12-05
2011-12-09
Works for both dates and datetime objects. Your second example:
>>> for result in perdelta(datetime.now(),
... datetime.now().replace(hour=19) + timedelta(days=1),
... timedelta(hours=8)):
... print result
...
2012-05-21 17:25:47.668022
2012-05-22 01:25:47.668022
2012-05-22 09:25:47.668022
2012-05-22 17:25:47.668022
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