There is no built-in function that counts occurences of substring in a string, but you can calculate the difference between the original string, and the same string without commas:
LENGTH(fooCommaDelimColumn) - LENGTH(REPLACE(fooCommaDelimColumn, ',', ''))
It was edited multiple times over the course of almost 8 years now (wow!), so for sake of clarity: the query above does not need a + 1
, because OPs data has an extra trailing comma.
While indeed, in general case for the string that looks like this: foo,bar,baz
the correct expression would be
LENGTH(col) - LENGTH(REPLACE(col, ',', '')) + 1
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