Python allows putting multiple open()
statements in a single with
. You comma-separate them. Your code would then be:
def filter(txt, oldfile, newfile):
'''
Read a list of names from a file line by line into an output file.
If a line begins with a particular name, insert a string of text
after the name before appending the line to the output file.
'''
with open(newfile, 'w') as outfile, open(oldfile, 'r', encoding='utf-8') as infile:
for line in infile:
if line.startswith(txt):
line = line[0:len(txt)] + ' - Truly a great person!
'
outfile.write(line)
# input the name you want to check against
text = input('Please enter the name of a great person: ')
letsgo = filter(text,'Spanish', 'Spanish2')
And no, you don't gain anything by putting an explicit return
at the end of your function. You can use return
to exit early, but you had it at the end, and the function will exit without it. (Of course with functions that return a value, you use the return
to specify the value to return.)
Using multiple open()
items with with
was not supported in Python 2.5 when the with
statement was introduced, or in Python 2.6, but it is supported in Python 2.7 and Python 3.1 or newer.
http://docs.python.org/reference/compound_stmts.html#the-with-statement
http://docs.python.org/release/3.1/reference/compound_stmts.html#the-with-statement
If you are writing code that must run in Python 2.5, 2.6 or 3.0, nest the with
statements as the other answers suggested or use contextlib.nested
.
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