C++ : Turn char array into a string that is printed

Question

just a beginner student learning basic C++. I'm trying to figure out the best way to:

1. Turn a char array Name of 20 into a string that can be printed. I found in other Stack Overflow topics to use "str()" such as "str(Name)", but it always comes up 'identifier not found'.

   cout << "Name:" << str(Name) << endl;
   

2. Set a char array of 20 characters. For some reason, the following gives me errors when declaring. I've tweaked it so many times, but I cannot get why it won't give.

   TESCStudent.Name[20] = {'S','u','p','e','r','P','r','o','g','r','a','m','m','e','r',''};
   

Full code I have so far:

#include <iostream>
#include <conio.h>
#include <string>
using namespace std;

//Step 1
struct StudentRecord
{
char Name[20];
//Accessor
void printInfo() const;
};

void StudentRecord::printInfo() const
{
cout << "Name:" << str(Name) << endl;
}

int main()
{
//Step 2
StudentRecord TESCStudent;
TESCStudent.Name[20] = {'S','u','p','e','r','P','r','o','g','r','a','m','m','e','r',''};

//Step 3
TESCStudent.printInfo();

_getch();
return 0;
}

Answer 1

Given that you are at a very beginner level, just use std::string:

#include <iostream>
#include <conio.h>
#include <string>

struct StudentRecord {
    std::string Name;
    void printInfo() const {
        std::cout << "Name:" << Name << '
';
    }
};

int main() {
    StudentRecord TESCStudent;
    TESCStudent.Name = "SuperProgrammer";
    TESCStudent.printInfo();

    _getch();
}

Live demo