Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
200 views
in Technique[技术] by (71.8m points)

symbolic references - How can I use a variable as a variable name in Perl?

I need to achieve the following in perl

printmsg(@val1, $msg1) if @val1;
printmsg(@val2, $msg2) if @val2;
printmsg(@val3, $msg3) if @val3;
printmsg(@val4, $msg4) if @val4;
printmsg(@val5, $msg5) if @val5;
printmsg(@val6, $msg6) if @val6;

So i wrote the following snippet

for(my $i=1; $i < 6; $i++ ) {
    printmsg(@val$i, $msg$i) if @val$i;
}

It doesn't work and breaks out with errors.

Question&Answers:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Whenever you find yourself postfixing variable names with an integer index, realize that you should have used an array instead:

my @msgs = ('msg1', 'msg2', ..., 'msg6');
my @vals = ( [ @val1 ], [ @val2 ], ..., [ @val6 ] );

See also the FAQ How can I use a variable as a variable name?

As the answer to the FAQ notes, if the variables are not indexed by an integer, you can use a hash table:

By using symbolic references, you are just using the package's symbol-table hash (like %main::) instead of a user-defined hash. The solution is to use your own hash or a real reference instead.

$USER_VARS{"fred"} = 23;
my $varname = "fred";
$USER_VARS{$varname}++;  # not $$varname++

You should read the entire FAQ list at least once a year.

Update: I purposefully left symbolic references out of my answer because they are unnecessary and likely very harmful in the context of your question. For more information, see Why it's stupid to 'use a variable as a variable name'?, part 2 and part 3 by mjd.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...