c# - Why does the Equals implementation for anonymous types compare fields?

Question

I'm just wondering why designers of the language decided to implement Equals on anonymous types similarly to Equals on value types. Isn't it misleading?

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void ProofThatAnonymousTypesEqualsComparesBackingFields()
{
    var personOne = new { Name = "Pawe?", Age = 18 };
    var personTwo = new { Name = "Pawe?", Age = 18 };

    Console.WriteLine(personOne == personTwo); // false
    Console.WriteLine(personOne.Equals(personTwo)); // true
    Console.WriteLine(Object.ReferenceEquals(personOne, personTwo)); // false

    var personaOne = new Person { Name = "Pawe?", Age = 11 };
    var personaTwo = new Person { Name = "Pawe?", Age = 11 };
    Console.WriteLine(personaOne == personaTwo); // false
    Console.WriteLine(personaOne.Equals(personaTwo)); // false
    Console.WriteLine(Object.ReferenceEquals(personaOne, personaTwo)); // false
}

At first glance, all printed boolean values should be false. But lines with Equals calls return different values when Person type is used, and anonymous type is used.

Answer 1

Anonymous type instances are immutable data values without behavior or identity. It doesn't make much sense to reference-compare them. In that context I think it is entirely reasonable to generate structural equality comparisons for them.

If you want to switch the comparison behavior to something custom (reference comparison or case-insensitivity) you can use Resharper to convert the anonymous type to a named class. Resharper can also generate equality members.

There is also a very practical reason to do this: Anonymous types are convenient to use as hash keys in LINQ joins and groupings. For that reason they require semantically correct Equals and GetHashCode implementations.