I have the path to a file i want to send to a rest webservice the server. I am using the xmlhttprequest object. The post is as follows:
var url = "http://localhost:8080/RestWSGS/jersey/gridsense";
var boundary = "--------------" + (new Date).getTime();
xmlHttp.open('POST', url, true);
xmlHttp.onreadystatechange = function ()
{
if (this.readyState != 4)
return;
var result =this.responseText;
document.write(result);
};
xmlHttp.setRequestHeader('Content-Type', 'multipart/form-data; boundary=' + boundary);
var part ="";
part += 'Content-Disposition: form-data; ';
part += 'name="' + document.getElementById("filename").name + '" ; ';
//alert(document.getElementById("filename").value);
part += 'filename="'+ document.getElementById("filename").value + '";
';
part += "Content-Type: application/xml";
part += "
"; // marks end of the headers part
part += 'filename="'+ document.getElementById("filename").value + '";
';
part+= data;
var request = "--" + boundary + "
";
request+= part /* + "--" + boundary + "
" */;
request+= "--" + boundary + "--" + "
";
alert(request);
xmlHttp.send(request);
The data i want to send is on the client local disk. I want to use the get method for it :
var str = document.getElementById("filename").value;
var data;
var xmlhttp1 = getNewHTTPObject();
xmlhttp1.open("GET",
"file:///New Folder/" +document.getElementById("filename").value , false);
xmlhttp1.send(null);
alert('hi' + xmlhttp1.status);
xmlhttp1.onreadystatechange = function() {
if (this.status == 0)
{
alert("resp " + this.responseText);
data = this.responseText;
}
}
The file:// does not work. If i put my file within the client directory and remove the file:/// then i can at least see xmlhttprequest open and give status 200 (i think ok!!). I read that for local file check status == 0 instead of readystatus == 4 so i did that but it still gives data variable as undefined and so the file does not go to the server. Initially when i had given the form action as my rest url it was uploading fine. Since I am not using html5 i cannot get the File object from the input type=file element. I want to use the xmlhttprequest object for this instead of the form element directly.
Please help me with this problem with any suggestions or hints
KAvita
Even if i do the uploading using form submission how can i use the return value of the web service. Thats the reason I need to use xmlhttpRequest. If anyone can suggest how the return value from the action is used it will be great!!
Kavita
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