To obtain the value, consider:
function ref(obj, str) {
str = str.split(".");
for (var i = 0; i < str.length; i++)
obj = obj[str[i]];
return obj;
}
var obj = { a: { b: 1, c : { d : 3, e : 4}, f: 5 } }
str = 'a.c.d'
ref(obj, str) // 3
or in a more fancy way, using reduce:
function ref(obj, str) {
return str.split(".").reduce(function(o, x) { return o[x] }, obj);
}
Returning an assignable reference to an object member is not possible in javascript, you'll have to use a function like the following:
function set(obj, str, val) {
str = str.split(".");
while (str.length > 1)
obj = obj[str.shift()];
return obj[str.shift()] = val;
}
var obj = { a: { b: 1, c : { d : 3, e : 4}, f: 5 } }
str = 'a.c.d'
set(obj, str, 99)
console.log(obj.a.c.d) // 99
or use ref
given above to obtain the reference to the containing object and then apply the []
operator to it:
parts = str.split(/.(?=[^.]+$)/) // Split "foo.bar.baz" into ["foo.bar", "baz"]
ref(obj, parts[0])[parts[1]] = 99
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