Let's break down your own argument:
According to the author,
j=j++;
is similar to
temp=j;
j=j+1; // increment
j=temp; // then assign
Yes, you're right so far..., but here's where you got it wrong:
But
a=b++;
makes b=1
. So it should've evaluated like this,
a=b; // assign
b=b+1; // then increment
WRONG! You're not applying the rule consistently! You've changed the order from increment then assign to assign then increment!!! It's actually evaluated like this:
temp=b;
b=b+1; // increment
a=temp; // then assign
Basically assignments of this form:
lhs = rhs++;
is similar to doing something like this:
temp = rhs;
rhs = rhs+1; // increment
lhs = temp; // then assign
Apply this to a = b++;
. Then apply it also to j = j++;
. That's why you get the results that you get.
What you did was you came up with your own interpretation of what a = b++;
does -- a WRONG interpretation that doesn't follow the above rule. That's the source of your confusion.
See also
- JLS 15.14.2 Postfix Increment Operator
"...the value 1 is added to the value of the variable and the sum is stored back into the variable [...] The value of the postfix increment expression is the value of the variable before the new value is stored."
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