How does Pythons double-sided inequality work? and why doesn't it work for numpy arrays?

Question

In Python you can do the following;

>>> 3 < 4 < 5
True
>>> 3 < 4 < 4
False

How does this work? I would have thought that 4 < 5 would return a boolean, and so 3 < True should return False, or 3 < 4 should return a boolean and so True < 4 should maybe return True if True could be cast as an integer 1?.

And why doesn't it work for numpy arrays?

>>> 1 < np.array([1, 2, 3]) < 3
Traceback (most recent call last):
  File "<input>", line 1, in <module>
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

Could it be made to work for numpy arrays?

question from:https://stackoverflow.com/questions/65849231/how-does-pythons-double-sided-inequality-work-and-why-doesnt-it-work-for-numpy

Answer 1

Per the Python docs:

Comparisons can be chained arbitrarily, e.g.,?x?<?y?<=?z?is equivalent to?x?<?y?and?y?<=?z, except that?y?is evaluated only once (but in both cases?z?is not evaluated at all when?x?<?y?is found to be false).

So your example is equivalent to:

1 < np.array([1, 2, 3]) and np.array([1, 2, 3]) < 3

so each subterm is expected to result in a boolean value. But the subterm:

1 < np.array([1, 2, 3])

results in a new numpy array containing:

[False, True, True]

It is this value that Python is trying to interpret as a boolean value. It fails to do that, producing the error message:

ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

I expect that the desired expression here is:

(1 < np.array([1, 2, 3])).all() and (np.array([1, 2, 3]) < 3).all()

which can't be simplified to use comparison chaining.