Is there a way to sweep through floats in python using a for loop?

Question

I'm trying to sweep through values of pi/24 to pi/2 in steps of pi/24. Currently I'm getting an error, with float object not being able to be interpreted as an integer. Is there any work around to this?

Sample of my code:

for theta in range(np.pi/24,np.pi/2,np.pi/24):
    v_initial_x = np.cos(theta)*velocity
    v_initial_y = np.sin(theta)*velocity

question from:https://stackoverflow.com/questions/65866236/is-there-a-way-to-sweep-through-floats-in-python-using-a-for-loop

Answer 1

It is because the built-in function range only takes integers. You can use numpy like so:

for theta in np.arange(np.pi/24, np.pi/2, np.pi/24):
    ''' Do your stuff here '''

Remember that the stop value is excluded from the range, so if you want to include that in your calculation, then you will have to add np.pi/24 to your stop value.