How to Deserialize json string inside string in Java using Jackson - MismatchedInputException

Question

Closed. This question needs debugging details. It is not currently accepting answers. question from:https://stackoverflow.com/questions/65542107/how-to-deserialize-json-string-inside-string-in-java-using-jackson-mismatchedi

Answer 1

something like this will work.

String t = ""{\"message\":\"test\"}"";
ObjectMapper mapper = new ObjectMapper();
mapper.enable(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT);
JsonFactory factory = mapper.getFactory();
JsonParser createParser = factory.createParser(t);
JsonNode actualObj1 = mapper.readTree(createParser);
TestModel t11 = mapper.readValue(actualObj1.asText(), TestModel.class);
System.out.println(t11.getMessage());

Below is the TestModel class

public class TestModel {
    
    public TestModel() {
    }
    
    @JsonProperty("message")
    private String message;

    public String getMessage() {
        return message;
    }

    public void setMessage(String message) {
        this.message = message;
    }
}