subprocess - Python - how to execute shell commands with pipe, but without 'shell=True'?

Question

I have a case to want to execute the following shell command in Python and get the output,

echo This_is_a_testing | grep -c test

I could use this python code to execute the above shell command in python,

>>> import subprocess
>>> subprocess.check_output("echo This_is_a_testing | grep -c test", shell=True)
'1
'

However, as I do not want to use the "shell=True" option, I tried the following python code,

>>> import subprocess
>>> p1 = subprocess.Popen(["echo", "This_is_a_testing"], stdout=subprocess.PIPE)
>>> p2 = subprocess.Popen(["grep", "-c", "test"], stdin=p1.stdout)
>>> p1.stdout.close()
>>> p2.communicate()
(None, None)

I wonder why the output is "None" as I have referred to the descriptions in the webpage : http://docs.python.org/library/subprocess.html#subprocess.PIPE

Had I missed some points in my code ? Any suggestion / idea ? Thanks in advance.

question from:https://stackoverflow.com/questions/9393425/python-how-to-execute-shell-commands-with-pipe-but-without-shell-true

Answer 1

From the manual:

to get anything other than None in the result tuple, you need to give stdout=PIPE and/or stderr=PIPE

p2 = subprocess.Popen(["grep", "-c", "test"], stdin=p1.stdout, stdout=subprocess.PIPE)