python - 从另一个Python脚本运行一个Python脚本，并传入参数[重复](Run a Python script from another Python script, passing in arguments [duplicate])

Question

This question already has an answer here:

(这个问题已经在这里有了答案：)

• What is the best way to call a script from another script?

  (从另一个脚本调用一个脚本的最佳方法是什么？)

  10 answers

  (10个答案)

I want to run a Python script from another Python script.

(我想从另一个Python脚本运行一个Python脚本。)

I want to pass variables like I would using the command line.

(我想像使用命令行一样传递变量。)

For example, I would run my first script that would iterate through a list of values (0,1,2,3) and pass those to the 2nd script script2.py 0 then script2.py 1 , etc.

(例如，我将运行我的第一个脚本，该脚本将遍历值列表（0,1,2,3）并将其传递给第二个脚本script2.py 0然后script2.py 1等。)

I found Stack Overflow question 1186789 which is a similar question, but ars's answer calls a function, where as I want to run the whole script, not just a function, and balpha's answer calls the script but with no arguments.

(我发现了Stack Overflow问题1186789 ，这是一个类似的问题，但是ars的答案调用了一个函数，在这里我想运行整个脚本，而不仅仅是函数，而balpha的答案则调用了脚本，但没有参数。)

I changed this to something like the below as a test:

(我将其更改为以下内容作为测试：)

execfile("script2.py 1")

But it is not accepting variables properly.

(但是它没有正确接受变量。)

When I print out the sys.argv in script2.py it is the original command call to first script "['C:\script1.py'].

(当我在script2.py中打印sys.argv ，它是对第一个脚本“ ['C：\ script1.py']的原始命令调用。)

I don't really want to change the original script (ie script2.py in my example) since I don't own it.

(我真的不想更改原始脚本（例如，在我的示例中为script2.py），因为我不拥有它。)

I figure there must be a way to do this;

(我认为必须有一种方法可以做到这一点；)

I am just confused how you do it.

(我只是很困惑你怎么做。)

  ask by Gern Blanston translate from so

Answer 1

Try using os.system :

(尝试使用os.system ：)

os.system("script2.py 1")

execfile is different because it is designed to run a sequence of Python statements in the current execution context.

(execfile有所不同，因为它旨在在当前执行上下文中运行一系列Python语句。)

That's why sys.argv didn't change for you.

(这就是sys.argv不会为您更改的原因。)