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javascript - JavaScript:将参数传递给回调函数(JavaScript: Passing parameters to a callback function)

I'm trying to pass some parameter to a function used as callback, how can I do that?

(我正在尝试将一些参数传递给用作回调的函数,该怎么做?)

function tryMe (param1, param2) {
    alert (param1 + " and " + param2);
}

function callbackTester (callback, param1, param2) {
    callback (param1, param2);
}

callbackTester (tryMe, "hello", "goodbye");
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1 Answer

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If you want something slightly more general, you can use the arguments variable like so:

(如果您想要更一般的东西,可以使用arguments变量,如下所示:)

function tryMe (param1, param2) {
    alert(param1 + " and " + param2);
}

function callbackTester (callback) {
    callback (arguments[1], arguments[2]);
}

callbackTester (tryMe, "hello", "goodbye");

But otherwise, your example works fine (arguments[0] can be used in place of callback in the tester)

(但是否则,您的示例可以正常工作(可以在测试器中使用arguments [0]代替回调))


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