Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.0k views
in Technique[技术] by (71.8m points)

linux - Command not found in Bash's IF-ELSE condition when using [! -d "$DIR"]

I have a code like this

#!/bin/bash 
DIR="test_dir/";
if [! -d "$DIR"]; then
    # If it doesn't create it
    mkdir $DIR
fi

But why executing it gave me this:

./mycode.sh: line 16: [!: command not found

What's the right way to do it?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Add space between [ and !. And before ] as well.

#!/bin/bash 
DIR="test_dir/";
if [ ! -d "$DIR" ]; then
    # If it doesn't create it
    mkdir $DIR
fi

It's also a good idea to quote your variable:

    mkdir "$DIR"

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...