Python to find dict in a list with particular key

Question

I have an array of lists with dicts as below:

[{'key': 'Platform', 'value': 'Test'}, {'key': 'Name', 'value': 'Test1'}, {'key': 'APICall', 'value': 'post'}]
[{'key': 'Platform', 'value': 'Test1'}, {'key': 'APICall', 'value': 'Get'}]
[{'key': 'Platform', 'value': 'Test2'}, {'key': 'Name', 'value': 'Test2'}, {'key': 'APICall', 'value': 'post'}]

for this array I would like to get the lists if keys Platform and Name present. So I would like to get [{'key': 'Platform', 'value': 'Test'}, {'key': 'Name', 'value': 'Test1'}, {'key': 'APICall', 'value': 'post'}] and [{'key': 'Platform', 'value': 'Test2'}, {'key': 'Name', 'value': 'Test2'}, {'key': 'APICall', 'value': 'post'}]

I don't know how to achieve this in one most effective way? I did a very simplistic way which is working, but in the future, if the list count grows then it might take a longer time. Is there any simple and effective way to achieve this?

for arr_keys in arr:
            if arr_keys['key'] == "Platform":
                platform = arr_keys['value']
            if arr_keys['key'] == "Name":
                Name = arr_keys['value']

Answer 1

The only improvement you can make without changing the formatting of the input is to break out of the loop once the keys 'Platform' and 'Name' are encountered.

platform = None
name = None
for arr_keys in arr:
    if arr_keys['key'] == "Platform":
        platform = arr_keys['value']
    if arr_keys['key'] == "Name":
        name = arr_keys['value']
    if platform is not None and name is not None:
        print(arr)
        break