Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
379 views
in Technique[技术] by (71.8m points)

javascript - RxJS: concat three promises, distinguish results

I have three promises, Rest requests returning lists of data.
The third one has references (ids) to the first two lists, so I want to map these ids to corresponding names when I have all the data.
The mapping isn't an issue, I just use Lodash for that.
But the issue is to wait for the three promises to resolve before starting to computing this mapping.

I figured out to use concat():

Rx.Observable.concat(p1, p2, p3).subscribe(
function onNext(list)
{
  // Assign the list to the corresponding variable in the scope
},
function onError(e)
{
  // Notify of error
},
function onCompleted()
{
  // Do the mapping
}
);

My problem is that onNext() will be called in random order. Ie. I don't know which list I receive at some point, and it is hard to tell from the data it contains.

Is there a way to track which promises produced which list? A kind of zip? concatMap? concatMapObserver? I admit I haven't fully understood the usage of the last two...

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

If these are promises we are talking about, I think you can have a look at the forkJoin operator. Cf. https://github.com/Reactive-Extensions/RxJS/blob/master/doc/api/core/operators/forkjoin.md, http://xgrommx.github.io/rx-book/content/observable/observable_methods/forkjoin.html

You could then have something like :

Rx.Observable.forkJoin(p1, p2, p3, function(p1,p2,p3){
/* your combining code here */
})

In short, forkJoin has semantics similar to that of RSVP.all if you know the promises library RSVP.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

2.1m questions

2.1m answers

60 comments

56.8k users

...